Virtusa(CEO-IT) 2022 Off Campus Drive Coding Questions And Answers

 

 

 

Virtusa(CEO-IT) 2022 OffCampus Normal Coding Questions And Answers:

 

1)  Print Palindrome If YES if the given string is a palindrome, else print NO as output.

 

Input: string

Output:  YES if the string is a palindrome else NO

Example:

Input:     level

Output:   YES

 

Input: Telugu

Output: NO

 

 

Code:

 

 

def isPalindrome(string):
    if string == string[::-1]:
        return 'YES'
    else:
        return 'NO'
        
print(isPalindrome(input()))

 

 

 

2) Print each word in the string in reverse for the given string which contains a number of words.

Input 1: The number of words in the string

Input 2: A string with input 1 number of words

Output: A string with each word in reverse order

Examples:

 

Input1: 11

Input2:  Telugu Tech Learners Is a Great youtube channel for job seekers

 

Output: uguleT hceT srenreaL sI a taerG ebutuoy lennahc rof boj srekees

 

 

Code: 

 

def stringWordsReverse(input1,input2):
    input2 = list(input2.split()) #first we will convert the string into a list of words
    string = "" # an empty string to append the reversed word of the input2 (string)
    
    for i in input2:       # we will iterate over each word
        string += i[::-1] + " " # we will reverse the word and append it to a string
    return string[:-1]   # string will contain space at last, remove it we will slice the string

input1 = int(input()) # input1 to store the number of words in the string
input2 = input()     # input to take the string with input1 number of words
print(stringWordsReverse(input1,input2))

 

3) Write A Program To Print The Number Of  Palindromes In A Given String.

Input1:  Input string containing words

Input2: The number of words in the string

Output: The number of palindromes in a string

Examples:

 

 

Input1: A level is completed

Input2: 4

Output: 1

Explanation: level is the only palindrome in the given string. So, the output will be one.

Input1: locol is upraisal werew youoy said

Input2: 6

Output: 3

Code:

 

 

def countPalindromes(input1,input2):
    input1 = list(input1.split())   # first we will convert the string as list of words
    count = 0       # count is initially zero
    for i in input1:     # iterating over the words in the list
        if i == i[::-1]:   # if word equal to reverse fo the word i.e., a palindrome
            count+=1   # coutn = count + 1
    return count
    

input1 = input() # input to take the string
input2 = int(input())    # input2 to store the number of words in the string
print(countPalindromes(input1,input2))

 

 

 4) Two Words Are Given If the second word can be formed from the first word then print YES, else print No

 Input1:  A word 

Input2: Another word 

 

Output:   YES if the input2 can be formed from Input1 by interchanging the letters in the word

Examples: 

Input1: word

Input2: rowd

Output: YES

Explanation: rowd can be formed from word by interchanging the word word

Input1: ttl

Input2: llt

Output: No

Explanation: llt cannot be obtained by interchanging the letter of ttl

Code:

 

 

code:

from itertools import permutations
def isWordFormed(input1,input2):
    
    # using permutations to find the number of words can be formed by interchaning the letters
    words = list(permutations(input1,len(input1)))

    #changing input2 to a tuple of its letters because perumations returns the words as tuples
    input2 = tuple(input2.strip())
    
    if input2 in words:   # if input2 in words
        return 'YES'    # return YES
        exit(0)         # and exit
        
    return 'NO'          # else return NO
    

input1 = input()
input2 = input()   
print(isWordFormed(input1,input2))

 

 

 

 

 

 5) Write A Program To Print A string by removing the duplicates in it.

Input1: A string containing words

Output: Uniques letters in the word in order

Examples:

 

Input: Good Morning

Output: God Mrni

 

Explanation: In the given string 'o', 'i', 'n' have duplicates, so the duplicates are removed. After removing duplicates we left with unique elements

 

 Code:

 

 

code:

def removeDuplicates(string):
    strs = ""         
    
     # iterating over the each letter in the string
    for i in string:   
        ''' if the letter is not in the strs we append it,
        if it already there in the strs we do not append '''
        if i not in strs:
            strs+= i
            
    return strs



string = input()
print(removeDuplicates(string))